2[z-(10z+69)+6]=3(z+7)

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Solution for 2[z-(10z+69)+6]=3(z+7) equation:


Simplifying
2[z + -1(10z + 69) + 6] = 3(z + 7)

Reorder the terms:
2[z + -1(69 + 10z) + 6] = 3(z + 7)
2[z + (69 * -1 + 10z * -1) + 6] = 3(z + 7)
2[z + (-69 + -10z) + 6] = 3(z + 7)

Reorder the terms:
2[-69 + 6 + z + -10z] = 3(z + 7)

Combine like terms: -69 + 6 = -63
2[-63 + z + -10z] = 3(z + 7)

Combine like terms: z + -10z = -9z
2[-63 + -9z] = 3(z + 7)
[-63 * 2 + -9z * 2] = 3(z + 7)
[-126 + -18z] = 3(z + 7)

Reorder the terms:
-126 + -18z = 3(7 + z)
-126 + -18z = (7 * 3 + z * 3)
-126 + -18z = (21 + 3z)

Solving
-126 + -18z = 21 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-126 + -18z + -3z = 21 + 3z + -3z

Combine like terms: -18z + -3z = -21z
-126 + -21z = 21 + 3z + -3z

Combine like terms: 3z + -3z = 0
-126 + -21z = 21 + 0
-126 + -21z = 21

Add '126' to each side of the equation.
-126 + 126 + -21z = 21 + 126

Combine like terms: -126 + 126 = 0
0 + -21z = 21 + 126
-21z = 21 + 126

Combine like terms: 21 + 126 = 147
-21z = 147

Divide each side by '-21'.
z = -7

Simplifying
z = -7

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